Practice OSSSC PEO 2023 math previous year questions with answers & explanations. Bilingual (English & Odia) interactive quiz data for quick revision!
1. Find the area and perimeter of a rectangle having a length of 12 cm and a breadth of 10 cm.
Area = length × breadth = 12 × 10 = 120 cm². Perimeter = 2 × (length + breadth) = 2 × (12 + 10) = 44 cm.
2. If the perimeter of an equilateral triangle is 27 cm, what is the length of its side?
Perimeter of an equilateral triangle = 3 × side. Side = 27 / 3 = 9 cm.
3. A mixture contains milk and water in the ratio 5:4. If 5 liters of water is added, the mixture ratio becomes 5:6. How much milk is there in the mixture?
Let milk = 5x and water = 4x. After adding 5 L water, 5x : (4x + 5) = 5 : 6. Therefore, 30x = 20x + 25, so x = 2.5. Milk = 5 × 2.5 = 12.5 liters.
4. The sum of two numbers is 25 and their difference is 13. Find their product.
x + y = 25 and x – y = 13. Adding gives 2x = 38 => x = 19. Then y = 6. Product = 19 × 6 = 114.
5. Find the simple interest on ₹4,000 at an annual rate of interest of 5% for 6 months.
SI = (P × R × T) / 100 = (4000 × 5 × 0.5) / 100 = ₹100.
6. Find the mean of the first 5 multiples of 8.
First 5 multiples of 8 are 8, 16, 24, 32, 40. Mean = (8 + 40) / 2 = 24.
7. Ram’s salary increased from ₹24,000 to ₹30,000. Find the percentage increase in his salary.
Increase = 30,000 – 24,000 = 6,000. Percentage Increase = (6000 / 24000) × 100 = 25%.
8. In the series 357, 363, 369…, what will be the 10th term?
First term (a) = 357, common difference (d) = 6. 10th term = a + 9d = 357 + 9(6) = 357 + 54 = 411.
9. Which one of the following numbers is divisible by 3?
Sum of digits of 4599 is 4 + 5 + 9 + 9 = 27, which is divisible by 3.
10. Find the perimeter of a square having an area of 144 cm².
Side = √144 = 12 cm. Perimeter = 4 × side = 4 × 12 = 48 cm.
11. If 15⁴ × 15ʸ = 15⁶, find the value of y.
Since bases are equal: 4 + y = 6 => y = 6 – 4 = 2.
12. In how many years will ₹3,100 become ₹6,200 at 4% simple interest per annum?
SI = Amount – Principal = 6200 – 3100 = 3100. Time = (SI × 100) / (P × R) = (3100 × 100) / (3100 × 4) = 25 years.
13. Find 8% of 625.
8% of 625 = (8 / 100) × 625 = 50.
14. After spending 30% of the money he took for shopping, Hari is left with ₹2,100. How much money had he taken for shopping?
Remaining money = 100% – 30% = 70%. 70% = 2100 => 100% = (2100 / 70) × 100 = ₹3,000.
15. Out of 200 persons, 140 like tea, 120 like coffee, and 80 like both tea and coffee. How many people like neither tea nor coffee?
Total liking at least one = 140 + 120 – 80 = 180. Neither = 200 – 180 = 20.
16. Which one has a larger perimeter: a square with a 1 cm long side or a circle with a 1 cm radius?
Perimeter of square = 4 × 1 = 4 cm. Perimeter of circle = 2πr = 2 × 3.14 × 1 = 6.28 cm. The circle has a larger perimeter.
17. The cost price of 11 pencils is equal to the selling price of 10 pencils. Find the profit percentage.
CP/SP = 10/11. Profit = 1 unit. Profit % = (1 / 10) × 100 = 10%.
18. The lengths of three sides of a triangle are in the ratio 1/2 : 1/3 : 1/4 and its perimeter is 78 cm. Find the lengths of its sides.
Ratio = 6:4:3 (multiplying by LCM 12). Sum = 13 units = 78 => 1 unit = 6 cm. Sides are 36 cm, 24 cm, 18 cm.
19. Convert the fraction 1/7 into percentage.
(1 / 7) × 100 = 100 / 7 = 14 2/7%.
20. What is the sum of the three interior angles of a triangle?
The sum of the interior angles of any triangle is always 180°.
21. In a 150-liter mixture of milk and water, water is 20%. How much more water should be added to make water 25% in the new mixture?
Initial milk = 80% of 150 = 120 L. In new mixture, milk = 75%. Total new mixture = 120 / 0.75 = 160 L. Water to add = 160 – 150 = 10 L.
22. The perimeter of a square courtyard is 100 meters. Find the cost of cementing it at the rate of ₹500 per square meter.
Side = 100 / 4 = 25 m. Area = 25 × 25 = 625 m². Total Cost = 625 × 500 = ₹3,12,500.
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